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*** Problem 3 When switch S in Figure 1 is open, the voltmeter V reads 3.08 V. When the switch is closed, the voltmeter readi

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Thanks for asking ..I=1.65A E=3.08 V, v=E-I8=2.97 3.08 -1.65x8= 2.97 = 8=0.06671 Ha due v=IR R = 2.97 - = 44.5su 0.0667 Power in resistance (R) =

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