Please show how to get the answer to part b
Please show how to get the answer to part b (10 pts) 6. The circuit shown...
*** Problem 3 When switch S in Figure 1 is open, the voltmeter V reads 3.08 V. When the switch is closed, the voltmeter reading drops to 2.97 V, and the ammeter reads 1.65 A. (Note: r is internal resistance of the battery.) fr Figure 1: Assume that the two meters are ideal so they don't affect the current in the circuit. a What is the EMF, V, produced by the battery? b) What is the liternal cesistance, r, of...
When switch S in the figure (Figure 1)is open, the voltmeter V of the battery reads 3.13 V . When the switch is closed, the voltmeter reading drops to 2.99 V , and the ammeter A reads 1.70 A . Assume that the two meters are ideal, so they don't affect the circuit.1) Find the emf.2) Find the internal resistance of the battery.3) Find the circuit resistance R.
When switch S in the figure is open, the voltmeter V of the battery reads 3.09 V . When the switch is closed, the voltmeter reading drops to 2.96 V , and the ammeter A reads 1.66 A . Assume that the two meters are ideal, so they do not affect the circuit. (Figure 1) - From that we find that emf E = 3.09 V.Find the internal resistance r of the battery.
9, A complete series circuit consists of a 12.0 V battery, a 4.70 Ω resistor, and a switch in the (1 point) closed position. The internal resistance of the battery is 0.30 2. What does an ideal voltmeter read when placed across the terminals of the battery? O12.0 V 024.0 V 02.40 V 11.3 10. A 1500 ΜΩ resistor is placed across the terminals of a battery, and a terminal voltage of 2.50 (1 point) V is measured, when this...
In the circuit shown in the figure (Figure 1) the batteries have negligible internal resistance and the meters are both idealized. With the switch S open, the voltmeter reads 13.0 V. Find the emf epsilon of the battery. What will the ammeter read when the switch is closed?
emf In the circuit above, the switch is closed for a short time. The readings are then recorded from the ammeter and the voltmeter and shown in the table below. Voltmeter Readings (V) Ammeter Readings (mA) 6.75 30 6.00 60 5.25 90 4.50 120 3.00 180 a) Draw a graph on graph paper of Voltmeter Readings against Ammeter Readings b) Find the following information from the graph: D) EMF of the battery b) Internal Resistance of the battery. c) A...
In the circuit shown in (Figure 1) the batteries have negligible internal resistance and the meters are both idealized. With the switch S open, the voltmeter reads 11.0 V.For related problem solving tips and strategies, you may want to view a Video Tutor Solution of A complex network.Part AFind the emf ε of the battery.Part BWhat will the ammeter read when the switch is closed?
In the circuit shown in the following figure, the voltage across the R1 = 5.50 Ohm resistor is 27.0 V. what are the emf of the battery and the current through the 6.00-Ohm resistor? (Let R2 = 1.00 Ohm) Epsilon = _____ V I = __________ A A capacitor is charged to a potential of 13.0 V and is connected to a voltmeter having an internal resistance of 3.45 Mohm. After a time of 3.50 s the voltmeter reads 3.0...
Complex Circuit problem. 3- Complex electric circuit Three equal resistors R are connected to a battery as shown in the figure below. The electric potential across the battery terminals when unconnected to this circuit is 9 V. Considering a value of r # 0.5 Ω for the internal resistance of the battery and a value of R- 5.5 2 for the three resistors, find 1. the voltage across the battery terminals when the switch is open 2. the voltage across...
Batteries are not perfect. They can't deliver infinite current. As the current load on a battery gets larger, the voltage output gets smaller. We can represent this by treating batteries as if they have some small internal resistance. The circuit below shows a battery hooked up to a resistor, a voltmeter (for measuring voltages), and an ammeter (for measuring currents). When you put a measuring device on something, like a circuit, you don't want to change the circuit. So this...