At STP we know that 1 mol contain 22.4 L
density of hydrocarbon 3.2215 gm/liter means 3.2215 gm in 1 L
i.e, 1L contain 3.2215 gm
22.4 L contain (3.2215*22.4) gm = 72.1616 gm
Hence 1 mol hydrocarbon = 72.1616 gm
Now 5 carbon atom = 5*12 = 60 gm
No of H atom = (72-60) =12
Hence the molecular formula is C5H12.(pentane)
BONUS Question: (8) A sample of a hydrocarbon compound (contains only carbon and hydrogen) is known...
A hydrocarbon (contains only carbon and hydrogen) was combusted. The sample combusted weighed 15.0mg. The products of the combustion were 27.0mg water and 44.0mg carbon dioxide. What is the empirical formula for the compound?
A hydrocarbon compound is known to be 86% carbon by weight and 14% hydrogen. In an experiment, 3.72g of this hydrocarbon were added to 50g of liquid benzene. The freezing point of this solution was 0.06 degree C. The normal freezing point of benzene is 5.5 degree C, and normal freezing point constant (K_ip) is 5.12 degree C/m. a. What is the molecular weight of the compound? b. What is the molecular formula of the hydrocarbon c. What is the...
2) A 1.000 g sample of a hydrocarbon (which is a compound that contains only carbon and hydrogen) was burned in oxygen, and the carbon dioxide and water produced were carefully collected and weighed. The mass of the carbon dioxide was 3.385 g, and the mass of the water was 0.692 g. What was the empirical formula of the hydrocarbon? A. C5H12 B. CsH6 C. CįH6 D. C H2 E. CįH star 1.00
CHAPTERS Practice Problems 6. An unknown gaseous hydrocarbon (compound composed of carbon and thydrogen only) conaists of 85.63% carbon by mass. A 0.335-g sample of the gas occupies a volume of 0.107 Lat STP (1 atm, oPC) What is the molecular formula of the gas7
a combustion analysis of a 0.2104 g hydrocarbon sample (containing only hydrogen and carbon) yielded 0.6373 g carbon dioxide and 0.3259 g water. A separate experiment determined that the molecular weight of this compound is 58.7 g mol-1. from this data, determine both emperical and the molecular formula of this substance.
3) A compound that is composed of only carbon and hydrogen is known as a(n): A) hydrocarbon B) isomer C) homolog D) carbohydrate 4) How many chiral carbon atoms are in this molecule? Он A) 0 B) 1 C) 3 D) 2 5) The compound CH3(CH2)4CH3 is called: A) heptane B) butane C) pentane D) hexane 6) What functional groups are present in the following structure? СHз-с"с-СH2ОН A) A ketone and an alkyne An aldehyde and a ketone B) An...
A 1.802 gram sample of unknown compound contains 0.721 grams of carbon, 0.121 grams of hydrogen and 0.960 grams of oxygen. The compound has a molar mass of 180.2 g/mol. Determine the empirical formula of the compound and the molecular formula. Show all work.
A sample of a hydrocarbon, containing just carbon and hydrogen, is combusted in air to produce 15.00 g CO2 and 9.20 g H2O.What mass of hydrocarbon was combusted? What is its empirical formula? Mass spectrometry indicated that the molecular mass of the compound is 75.1 g/mol. What is themolecular formulae?
A compound of molar mass 166 contains only carbon, hydrogen, oxygen, and bromine. Analysis shows that a sample of the compound contains six times as much carbon as hydrogen, by mass. Part A Calculate the molecular formula of the compound. Express your answer as a chemical formula. Enter the elements in the order: C, H, O, Br. C6H7O2Br5
12) The complete combustion of 0.645 g of a compo und that contains only carbon and hydrogen produces 1008 ml of CO2(g), measured at STP, and 0.945 g of H20. The 0.645 g gas sample occupies 351 ml at 50 c and 0.567 atm. What is the molecular formula of the compound? Setup: