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Assignment Score: 100/900 Resources Hint Check Answer Question 2 of 9 > Using a simple pulley and rope system, a crewman on a
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mi = 6:04 kg me 2012 by 4:26.5m. y = 1.50 ml h=14.7 m mza VVVVVUJU as the acceleration of block and man will be same T= mzatas & ie horisontal component of velocity of lawman, roman When we het the Mentreal Compe ground a tegh torka 9 X 260 Rey Ug =

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