Question

Part A A uniform magnetic field points upward, parallel to the page, and has a magnitude of 785 mT A negatively charged partico (g = -3.32 C. m = 205 pg) moves through this field with a speed of 67.3 km/s at a 42" with respect to the magnetic field, parallel to the page as shown. What is the magnitude of the magnetic force on this particle? 161 mN 1.75 m 1.30 m 1.17 m Submit Request Answer - Part B i n 2C 2.05 pg) moves through

Answer 1

& When field, the a charge charge particle particle moing through will experience a magnetic a force given 7 - 91xB) if the ci and B direction, the particle are along will not some of opposite experience and force to pent We know perpendicular can to decompose B. along and V coso Α Α Α Α = Usino v = vcoso, Usino Fm = 190, B1 =9uBgino = 3.32 X10 x 67.3 x103 x 7.85X10 ? sin442) = 1:17 X10-3N = 1.17 mN. 0 for the direction, E = - ² x9 = -², into the page /

cueil @ for move the motion along y of anies the charge particle while moving in a circle. the radices of the cine For let to be Circle, mot = 90B Ya mas - 9B yo - me 205 810 x 6703x10 3x sin42 m. B 3.32x106 x 7oung = 3.54x103 m = 3.54 mm i None of the answer is correct. But if one ignore the to component then it comes 5.29 mm, But factually this will not be the answer theoritically.