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2. For each of the following elimination reactions, draw a circle around the nucleophile/base, a star next to the acidic hydrogen, and a box around the leaving group, and an arrow pointing to the new bond formed in the product. (4 points) a. Br -OH CI b. CH3 CH3 C. lr CH3OH d. Ph CH3 H CH3Hi I really need help solving this and could you explain it as well?

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Answer #1

This all reaction are elimination reactions.

In elimination reaction , the base approach to acidic hydrogen.

In elimination reaction acidic hydrogen removes from beta carbon

And leaving group removes from alpha carbon.and new pie bond forms.

он .Η ce CH3 Eto CM3 Cu +на Kt Saved

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