Question

1-24 need help really lost

Proton Transfer: deprotonation D. 1) Add the appropriate curved arrows for the following deprotonation step. Also add the other product notice how the Tema s can be converted to this by use of a strong base such as sodium a sodium ion (Na) is not drawn, in this case it is just a spectatorio PCW27 - Mechanistic steps - Part Name: Time spent 2) Label the above compounds with the appropriate name from the previous sentence they are underlined) Also label ammonia 3) Why is the sodium ion (Na) considered a spectator ion? The proton transfer is possible because the proton on the terminal alkyne is more acidic compared to other H bonds. 4) Recal the following pa's: alkane CH_ alkene CH_ alkyne CH- 5) Using your knowledge of electronegativity and polar bonds draw the partial charges (6 or 8) on the following structures: (each structure should have at least one carbon labeled) MOB mu i one yg mer 6) A few of the above molecules are classified as organometallic reagents because they have a metal carbon bond. Circle the organometallic reagents above. It is often useful to think about organometallic reagents as salts (ion-pairs) and ignore the cation 7) Draw the simplified structures of the three organometallic compounds above they should be carbanions), 8) What do the carbons of each metal-carbon bond have in common? 9) What partial charge or 8) would have in a metal hydrogen bond (M-H? H ) and We call these species hydrides . The most common hydride reagents are sodium borohydride ( N lithium aluminum hydride (LLAH). For now consider B and LLH as hydride sources: Substitution Bimolecular 10) How many molecules are involved in an mechanistic step? Hint it's in the name 11) Label the electrophile electron poor species) and nudeophile electron rich species) in the reaction below. It may help to identify the electron rich species first it will typically have lone pairs and/or a negative charge)

Answer 1

The given reaction is a deprotonation reaction which occurs because of acidic nature o terminal alkynes. DONH2 + H-CIT Amide ion) L 1 (IUPAC name! But-1-yre) Cach + NHz (Acetylice) (Ammonia) 27 Labelling is shown above. Amide ion + But-l-une (terminal - alkyne) Acetylide + Ammonia lectator ions are those which exist in the same form in both reactants and product. This in remains unchanged on both sides of the reaction and hence does not affect the equilibrium Nat is called spectator ion and often ignored while writing the Chemical reaction Pka no) 47 Alkane uso Alkene nu3 Alkyne 125 pkas value show that (terminal celkynes) celkynes are most acidic out of alkane, celkene and alkynes lower pka high acidity.