Change in momentum = impulse provided = Fdt = Area under curve.
p(t=0) = 0
a)
p(t=4) = p(t=0) + impulse = 0 + 0.5*2*10 + 10*2
p(t=4) = 30 kg.m/s
b)
p(t=7) = 0.5*2*2*10 + 10*2 - 0.5*1*5
p(t=7) = 37.5 kg.m/s
c)
p(t=9) = 0.5*2*2*10 + 10*2 - (2*0.5*1*5 + 5*1)
p(t=9) = 30 kg.m/s
v = 30/5 = 6 m/s
please write out formulas as if i have no idea about physics. i know that this...
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