Question

Using matlab...

Calculating with vectors. Compute the following values. The value of N will be randomized at each submission and will be created by the auto grader. Do not modify the given value of N. Note: N will be a positive integer 2 1. o Compute the mathematical expression below and store the result in the variable named x. Your code should work for any positive integer N given. 2N 1 1 2 3 4 o Hint: Create a numerator vector of [3.5,7..2 N+1] using the colon operator o Hint: Create a denominator vector of [1,2,3, .., N] using the colon operator. o Hint: Then do the array division (-/), and use sum function. Compute the mathematical expression below and store the result in the variable named y. Your code should work for any positive integer N given. 3 o Hint: Note that [2, 4, 8,... 2N] is the same as [21, 22,23., 2 o Hint: Use array exponentiation (.^), on the vector [1,2,3, , N], and use sunm function. o Hint: 2,2,2]./[10,20,30] is the same as 2./[10,20,30]

Answer 1

load('setup.mat','N')

x=0;

y=0;

%-------------------------------------------------calculating x------------------------------------------------

num = [3:2:(2*N)+1]; %creating vector that starts with 3 with a difference of 2 till (2*N + 1)

den = [1:N]; %creating vector that starts with 1 till N

x = sum(num./den); %first dividing each element in both vectors and then taking sum

%-------------------------------------------------calculating x------------------------------------------------

%-------------------------------------------------calculating y------------------------------------------------

%for y numerator is simply 3

den = 2.^den; % using denominator as defined for x but slightly modifying it to become 2 raise to power of den

y=sum(3./den); %finally, dividing 3 to each den vector element and then taking the sum

%-------------------------------------------------calculating y------------------------------------------------

%OUPUT: To test taking n=10, we get x=22.929 and y=2.9971

>> N=10; > n >> den = [1:N]; >> x = sum (num. /den) x22.929 >> den = 2.den; >y sum (3./den) y= 2.9971 um[3:2: (2 N) +1]: