Question

Student ID: 123

Write a C+ program with the following specifications: a. Define a C++ function (name it function_StudentlD where StudentID is your actual student ID number) that has one integer input (N) and one double input (x) and returns a double output S, where N S = n 0 and X2 is given by 0 xeVn n 0,1 Хл —{2. nx 2 n 2 2 m2 x2 3 (Note: in the actual quiz, do not expect a always, practice if-else, switch simple su m statements, for/while loops, functions with multiple inputs, other mathematical functions such as sin, cos, remainder, exponentiation, etc.). b. n the main function, i. Read user input for N from the command window (console), while ensuring that N is positive >0) integers. If the user enters non- positive number, the program should request the user to re-enter a positive (>0) number until a valid number is entered ii. Use the above function (function_StudentlD) to determine the sum S for the user input N when x 2.o. Display the result using 5 decimal values iiUsing the above function and a for loop, display the values of S for x = 2.0 and N values from 1 to 10 (1,2,3,..,10). Also write the resulting values to a file named "sum.txt". Display the result using 5 decimal values in all outputs (file and command windows)

Answer 1

#include <bits/stdc++.h>
using namespace std;

const double e = 2.71828;

// Part a
// This function get's an integer N and doubel x
// It calculates values for all i -> [0,N]
// according to given formula, and returns sum.
double function_123(int N, double x) {
double sum = 0;
for (int i = 0; i <= N; i++) {
if (i == 0 || i == 1)
sum += x * pow(e, sqrt(i));
else
sum += (2.0 * sqrt(i / 2.0) + i * x) / (pow(i / 3.0, 2) + x * x);
}
return sum;
}

int main() {

// Part b.I
//This cycle asks user to enter N
//In case of negative number error is written
//and user is asked for input again
int N = 0;
while (true) {
cout << "Enter N: ";
cin >> N;
if (N > 0)
break;
cout << "Invalid input. Enter positive number.\n";
}

// Part b.II
// Answer for user's N and x = 2.0 is printed on console
cout << fixed << setprecision(5) << "Result: " << function_123(N, 2.0)
<< endl;

// Partn b.III
// Answer for N -> [1, 10] is written to sum.txt file
ofstream writer;
writer.open("sum.txt");
for (int i = 1; i <= 10; i++)
writer << fixed << setprecision(5) << function_123(i, 2.0) << endl;
writer.close();

return 0;
}

OUTPUT

Input (stdin) -5 Your Output (stdout) Enter N: Invalid input. Enter positive number Enter N: Invalid input. Enter positive number Enter N: Result: 10.47646

ntr File Edit Format View Help 7.43656 8.78656 10.47646 12.35061 14.29258 16.22560 18.10413 19.90413 21.61510 23.23458

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