Question

Consider making a function (mini program to complete a specific task) for each of the scenarios below. State what the purpose of the function is in your own words, specify input that is needed by the function, what output is expected from the functions, and the step by step process that will obtain the output from the input (the algorithm). In addition to these 4 items also specify test data that can be used for each problem. Remember to describe your steps in enough detail so someone other than you could follow your algorithm and solve the problem. Also do not write any actual code. However as you list the steps, you may want to employ statements such as “repeat steps 2-4 until n is reached. Problem 1: Create a process that will calculate the series 1 + x + x2 + x3 + x4 ………. + xn where x is a floating point number and n is a positive number. You process should be designed so exponentiation functions are not needed. Problem 2: Write a process that will complete will find the sum of the following series. (Again do not use any exponentiation functions). 1/n + 2/(n-1) + 3/(n-2) + ………. + n/1 Program 3: Write a process to determine the average of values entered by the user. These values should be entered one at a time (do not use concept of arrays or lists).

Answer 1

copy to code:

#include <iostream>

using namespace std;

/*this function will calculate 1 + x + x2 + x3 + x4 ………. + xn*/

float calculateExponentialSeries(float x, int n){

//first value of series 1 store in the result

float result = 1;

//it will store the power value of element

float powerX;

//print first 1 of series

cout<<"1 ";

//loop until n

for(int i=1;i<=n;i++){

powerX=1;

//calculate the power of x for i

for(int j=1;j<=i;j++){

powerX*=x;

}

//print x and x2 based on input

cout<<"+ "<<x<<"^"<<i;

//set result to input

result+=powerX;

}

//print result

cout<<" = "<<result<<endl;

return result;

}

/*this function will calculate 1/n + 2/(n-1) + 3/(n-2) + ………. + n/1 */

float calculateDiffSeries(int n){

float result = 0;

//it will store the divide value of elements

float differentialValue;

//loop till n

for(float i=1;i<=n;i++){

//calculate the value

differentialValue = i/(n+1-i);

//store in result

result+=differentialValue;

//print series

cout<<i<<"/"<<"("<<n<<" - "<<i-1<<") ";

if(i!=n){

cout<<"+";

}

}

cout<<" = "<<result<<endl;

return result;

}

/*this function will calculate average of values entered by the user.*/

float averageOfValue(){

cout<<"Enter the values . 0 to exit"<<endl;

float input=-1,noOfInput=0,total=0;

cin>>input;

//ask user input until 0 entered

while(input!=0){

//increase the number of input by 1

noOfInput++;

//add input to total

total+=input;

//ask for next input

cin>>input;

}

//calculate the average

float average = total/noOfInput;

//print average

cout<<"Average is "<<average;

return average;

}

//main function calling all other function

int main(){

calculateExponentialSeries(2,9);

calculateDiffSeries(2);

averageOfValue();

return 0;

}

output:

Console X terminated> firstHello.exe [C/C++ Application] CAUsers)Mohammad Shahrukh) cPP\firstHello D 1/ (2-0) +2/(2-1) = 2.5 Enter the values. 0 to exit 12 13 14 0 Average is 13