Question

Write a working C program that will do the following:

1. Include your name, Lab Test number, and studentId as comments in the first lines of the program

2. User is first prompted to enter an integer number between 1 and 20, to be stored as variable named number. If the number is outside the range 1-20, the program will end.

3. If the number is within the allowed range, variable number is passed to function multF(). The multF() function computes and returns the result of: 1 x 1/2 x 1/3 x …. x 1/n using a loop, where n is a number entered by the user.

4. The result is then returned to main() and displayed on the screen (from main()!).

Answer 1

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Program

#include<stdio.h>

//Function to calculate
double multF(int n)
{
double res=1;
for (int i=1; i<=n; i++) //Loop
res =res*((double)1/(double)i);
return res;
}

int main()
{
double result;
int number;
  
   //Reading input
printf ("Enter a number between 1 and 20 :");
scanf ("%d",&number);
  
   if((number<=20)&&(number>=1))
   {
   //Calculating series
result=multF(number);

   //Printing results
   printf("Result = %lf\n",result);
   }
   else
       printf("Wrong Input !!!\n");
   return 0;
}

Output

Enter a number between 1 and 20 :21
Wrong Input !!!

Enter a number between 1 and 20 :0
Wrong Input !!!

Enter a number between 1 and 20 :21
Wrong Input !!!

Enter a number between 1 and 20 :1
Result = 1.000000

Enter a number between 1 and 20 :2
Result = 0.500000

Enter a number between 1 and 20 :3
Result = 0.166667

Program Screenshot

#include<stdio.h> //Function to calculate double mult(int n) { double res=1; for (int i=1; i<=n; i++) // Loop res =res*((double) 1/(double)i); return res; ببا int main() { double result; int number; //Reading input printf ("Enter a number between 1 and 20 :"); scanf ("%d",&number); if((number<=20)&& (number>=1)) { 1/Calculating series result-multF(number); 1/Printing results printf("Result = %lf\n",result); } else printf("Wrong Input !!!\n"); return 0;