Using equation
v^2 = u^2 + 2*a*d
u = 35*5/18 = 9.72 m/s
0 = 9.72^2 - 2*a*40
a = 1.18 m/s^2
Now for second condition
u = 70*5/18 = 19.44 m/s^2
Using formula
0 = 19.44^2 - 2*1.18*d
d = 160.13 m ...... Minimum distance required
Problem #6 (Extra Credit) The minimum distance required to stop a car moving at 35 km/hr...
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