Question

Derive the Jones matrix, Eq. (14-15),representing a linear polarizer whose transmission axis is at arbitrary angle θ with respect to the horizontal #question: anyone can help to solution it by use method in second image. ***** thoroughly solution ********

M-Linoso, cos2 θ sin θ cos θ sin θ cos θ linear polarizer, TA at θ (14-15) sin 2 θ

Answer 1

Let's Assume that the components of a beam emerging from a polarizing element are linearly related to the components of the incident beam. This relation is written as: E''_x = j_xx E_x + j_xy E_y E'_y = j_xy E_x + j_yy E_y Where, E_x' and E_y' are components of emerging beam, and E_x and E_y are components of incident beam. The quantities j_1k, i, k = x, y are transforming factors. The above relations can be written in matrix forms [E_x' E_y'] = [j_xx j_yx j_xy j_yy] [E_x E_y] or E' = J middot E Now putting in (replacing) the values for E' & E_1 and assuming j_xx = a, j_xy = b, j_yx = c and j_yy = d we get For axis Parallel to axis of polarizer [a c b d] [cos theta sin theta] = [cos theta sin theta] (horizontal polarized can horizontally polarized field) \r\n The equations can be written as a cos theta + b sin theta = cos