Describe the relationship of activation energy with rate of reaction and the effect a catalyst has...
8. (20 points) Consider the following mechanism, with the accompanying energy diagram, which has been suggested for the following overall reaction in the presence of a Cl catalyst: 03 +0 202 Step 1: Step 2: 03 + Cl → OCl + O2 OCl + 0 + 02 + Cl +---Ea, Energy - - - - AHrxn --- - Reaction progress- A. Based on the energy diagram, which step is rate limiting? Which step is the fastest? (4 Points) B. Identify...
The reaction can be speeded up by using a catalyst that reduces the activation energy. The most popular catalysts are based on iron (Fe) and ruthenium (Ru). The table shows the variation in the concentration of Nz(g) as a function of time for a reaction carried out at 500 °C and 200 atm in the presence 0 0.1 0.2 0.3 0.4 0.5 0.6 of an Fe catalyst:. IN,(e)] (mol/L) 2.00 1.68 1.42 1.19 1.01 0.846 0.710 7. Use these data...
8. The rate law for the reaction H2O2 + 2H+212 + 2H2O is rate-k[H202][1]. The following mechanism has been suggested. H2O2+1 - HOI + OH - slow OH + H H20 fast HỘI + H+ + + I2 + H2O fast Identify all intermediates included in this mechanism. A) H and I D) Honly B) H and HOI E) H20 and OH C) HOI and OH 9. Which of the following statements is false? A) A catalyst increases the rate...
The reaction can be speeded up by using a catalyst that reduces the activation energy. The most popular catalysts are based on iron (Fe) and ruthenium (Ru). The table shows the variation in the concentration of N2(g) as a function of time for a reaction carried out at 500 °C and 200 atm in the presence 0 0.2 0.3 0.4 0.5 0.6 of an Fe catalyst: [N,(e)] (mol/L) 2.00 1.68 1.42 1.19 1.01 0.846 0.710 0.1 7. Use these data...
1. The following mechanism has been proposed for the pas-phase reaction of chloroform and chlorine Ch> 20 (fast) CI + CHCI, - HCI +CCI, (slow) Cl + CCI - CCI (fast) a) Identify any intermediate(s): b) Identify any catalyst(s): b) Write the balanced equation for the overall reaction: c) Molecularity of each step: step 1. step 2. step 3 d) rds (circle): 1 2 3 d) What is the observable rate law predicted by this mechanism? e) What is the...
2. Consider this two step mechanism for a reaction… Step 1 NO2 + O3 --> NO3 + O2 slow; rate determining step Step 2 NO3 + NO2 --> N2O5 fast a. What is the overall reaction? b. Identify the intermediates in the mechanism. c. Write the rate law expression for each step of the mechanism including any reversible reactions. c. What is the predicted rate law expression? Be sure to only list reactants from the overall equation and not intermediates...
When a graph of energy vs, reaction progress was graphed for the reaction A + B rightarrow C + D, the following data was obtained: a) Draw a rough sketch of what this activation energy diagram looks like. Make sure axes and points are labeled appropriately. B) What is the numerical value of the activation energy obtained from the graph? c) Are reactants or products more stable? d) Is the reaction endothermic or exothermic? Explain. d) On the graph you...
1. Write a rate law from the image below: TRANSITION STATES Ea(step 2) Ea(step 1) slow fast Potential energy NO2F+ F+NO2 2NO2 + F2 REACTANTS ΔΗ 'nxn <0 2NO2F PRODUCT Reaction progress A. Rate = k [NO2] B. Rate = k [NO2][F2] C. Rate = k [NO212[F2] 2. What is the overall reaction? A. 2 NO2 + F2 → 2 NO2F B. NO2 + F2 → NO2F +F + NO2 C. NO2 + F2 → 2 NO2F 3. Write out...
3a. Write the overall reaction equation for the following mechanism. Identify the intermediates. fast slow fast 02 20 O+N2 NO N b. The rate law for the following mechanism is rate kIN2] [O]. Show how this can be determined from the mechanism. c. Draw a possible energy diagram for this reaction and show the location of the reactants, products, and intermediates. Reaction progress
Can you please answer the following questions? The rate constant, k for the reaction below A - Products is 2.8 x 10 sat 80°C. If the initial concentration of A is 0.25M, what is the concentration after 50 s? The oxidation reaction of thallium (I) by cerium (IV) is believed to occur via three steps. The rate low for the reaction is: rate = k[Ce [Mn2") ce". Mne - Cen ! ce". Mn. Cell. Mn TI". Mn* - TI. Mn?...