2. (20 points) Find the solution y (t) of the following differential equation: -{ 0t< 4...
(1 point) Consider the following initial value problem: y" +9y (st, o<t<8 y(0) = 0, '(0) = 0 132, ?> 8 Using Y for the Laplace transform of y(t), i.e., Y = C{y(t)} find the equation you get by taking the Laplace transform of the differential equation and solve for Y(8)
Find a general solution to the given equation for t<0. y''(t) – Ły'(t) + 5 -y(t) = 0 t The general solution is y(t) = (Use parentheses to clearly denote the argument of each function.)
(1 point) Consider the following initial value problem: 4t, 0<t<8 \0, y" 9y y(0)= 0, y/(0) 0 t> 8 Using Y for the Laplace transform of y(t), i.e., Y = L{y(t)} find the equation you get by taking the Laplace transform of the differential equation and solve for Y(s)
Problem 4. (25 points) Find the solution to the 2-dimensional Laplace's equation OLY + = 0 inside the square 0<x<1 0 <y <1 subject to the boundary conditions V(x,0) = 0 = V(x, 1) V(0,y) = 0 V(1,y) = 2 sin (31 y)
PROBLEM 1 IS SUPPOSED TO BE A WAVE EQUATION NOT HEAT EQUATION 1. Find the solution to the following boundary value initial value problem for the Heat Equation au 22u 22 = 22+ 2 0<x<1, c=1 <3 <1, C u(0,t) = 0 u(1,t) = 0 (L = 1) u(x,0) = f(x) = 3 sin(7x) + 2 sin (3x) (initial conditions) (2,0) = g(x) = sin(2x) 2. Find the solution to the following boundary value problem on the rectangle 0 <...
Problem 2: [Also challenging] Find the solution of the following IVP: y' +2y = g(t), with y(0) = 3 where g(t) = - 0<t<1: g(t) = te-2 > 1.
Find the solution of the given initial value problem: y" + y = f(t); y(0) = 6, y'(0) = 3 where f(t) = 1, 0<t<3 0, įst<<
Find the Laplace transform Y(s)=L{y} of the solution of the given initial value problem. Enclose numerators and denominators in parentheses. For example, (a−b)/(1+n). y" +9y S t, 0<t<1 1, 1<t< , y(0) = 7, y' (0) = 4
Q4 a) Find the general solution of the differential equation Y') + {y(t) = 8(6+1)5; 8>0. Y'8 8 >0. 8(8-1)3 b) Find the inverse Laplace transform y(t) = £ '{Y(3)}, where Y(s) is the solution of part (a). c) Use Laplace transforms to find the solution of the initial value problem ty"(t) – ty' (t) + y(t) = te, y(0) = 0, y(0) = 1, for t > 0. You may use the above results if you find them helpful....
Solve y'' +9y = $(t – 6), y(0) = y'(0) = 0 g(t) = for t < 6 for t > 6