Question

Steven carefully places a m 1.95 kg wooden block on a frictionless ramp so that the block begins to slide dawn the ramp from rest. The ramp makes an angle of 55.3° up from the horizontal. Which forces do nonzero work on the block as it slides down the ramp? Прагпн! friction gravity spring How much total work has been done on the block after it slides down along the ramp a distance of 1.93 m? total work done on the block: Nancy measures the speed of the wooden block after it has gone the 1.93 m down the ramp. Predict what speed she should measure. final speed after sliding from rest: m/s Now, Steven again places the wooden block back at the top of the ramp, but this time he jokingly gives the block a big push before it slides down the ramp. If the block's initial speed is 2.00 m/s and the block again slides dawn the ramp 1.93 m, what should Nancy measure for the speed of the block this time? final speed after sliding with initial speed 2.00 m/s: m/s

Answer 1

Since only two faces is acting on the block as it seides down the nump namely, the gravity and the normal. Therefore, the force that do non-zero work on the block is gravity distance of the nump d = 1.93m Expression for total work done as it slides down is W = mg sino ad W = 1.9589 9x sin 155.31x193 = 30 32J Expression for work energy tharm b muz-W +x195xU2=30.32 =) V=5.58 m/s Here initial speed of block out I'm lu2u²/=W $11.95 (U12 - 41 = 30.32 v=5.92 mis