Question

A block is placed on a frictionless ramp at a height hof 14.5 m above the ground. Starting from rest, the block slides down the ramp. At the bottom of the ramp, the block slides onto a frictionless horizontal track without slowing down. At the end of the horizontal track, the block slides smoothly onto a second frictionless ramp. 0 = 48.3° By = 25.5 How far along the second ramp does the block travel before coming to a momentary stop, as measured along the incline of the ramp? distance traveled along second ramp: 10.69 After the block comes to a complete stop on the second ramp, it will then begin moving back down the second ramp. What ho hleck when it is 7.75 m. vertically, above the ground?

Answer 1

using conservation of energy

pE on left ramp = potential energy at right ramp

mg h1 = mg h2

14.5 = d sin 25.5

d = 33.681 m

===≠=

b)

using energy conservation

0.5 m v^2 = mg (h1 - h)

0.5 v^2 = 9.8* ( 14.5 - 7.75))

v = 11.502 m/s

======

Comment before rate in case any doubt, will reply for sure.. goodluck