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A wheel with mass of 5 kg and a radius of 15 cm is mounted so...

A wheel with mass of 5 kg and a radius of 15 cm is mounted so that it spins on an axle through its center. A light-weight string is wound around the circumference of the wheel. If a constant force of 3.0 N is applied to the end of the string for 1.0 seconds, what will be the change in the angular velocity? (Model the wheel as though it were a uniform cylinder.)

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Answer #1

Applying Net torque = I alpha

R F =( M R^2 / 2 ) alpha

1*3 / (5 * 0.15) = alpha

alpha = 4 rads^2


Applying theta = w0 t + alpha t^2 / 2

theta = 0 + (4.0)(1^2) /2

= 2 rad .........Ans

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