Question

Please help to find the pH

A chemist titrates 2200 mL of a 05950 M hydrochloric acid (lici) solution with 0.3559 M KOH solution at 25 ℃ Calculate the pH at equivalence. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of KOH solution added. pH

Answer 1

HCl KOH KCl H20 strong acid strong base neutral salt at equivalence point number of moles of acidnumber of moles of base only neutral salt KCI present so pH 7.00 Calculating number of moles of acid: molariy of HCI0.5950 M volume of HCl - 220.0 mL0.22 L number of moles of HCI- number of moles of HCI - number of moles of HCI0.5950 x 0.22 number of moles of HCl0.1309 mol Molarity x volume - Molarity of acid0.595 M V. volume of acid 0.22 L ,Molarity of base 0.356 M V -volume of base 0.595 x 0.22 0.356 x V2 0.131 0.356x V2 volume of base 0,368 M