Question

Which of the following solutions would require the quadratic equation to calculate the pH without a substantial error?

A. 0.10 M HCl(aq)

B. 0.10 M CH3COOH (aq), Ka(CH3COOH) = 1.8 x 10−5

C. 0.10 M KCN(aq), Ka(HCN) = 4.9 x 10−9

D. 0.10 M KHSO4(aq), Ka(HSO4–) = 1.3 x 10−2

Answer 1

DATE 0.10M of Hel Со с 0:1ом Hel is a soprong Acid d if dissociate complete into cons o no d cao Hol BeFone : G > Ho & Co o o Гер: o o o Ги+] . Също. Госу М. - Г») - - ego-10) ka - "g or s Con 0.10M ce, Leon (@) = to ooo toa) t и® (99) to mith аllу :. . o o — Af equilibriumi-Colta) lod cool Ге) си, ог) — tC, et) (co < ) си, сооп7 (1-е) 5) "s rtbr s a com , o-10 от

0.1002 0.1002 , 18*** Urd 1.8 xsort +02 1881005 to 10 ofto 18 x 10-5 22 = (1-0) (18 r1ors) x 2 + (184105 - 1881os no x2 + 18 81001 - 184905 to I quadratic equation. quadratic aquatim we will by solving find this a After finding & (4+1 = Cod 20.100 pH = -log {1+] = -log (0.100) ked dissociate fout Completely qt is into belt the & it solution coa oilom.

key (4) ekt (os) + су в 19) — miya, 414e. : c. o o o o o — Гу-2 : Со я о. )ом. Ооо. - HEN ² HO + NO ko {sf] = [cneja ollon pМ. - Реј Си*) D) R 450% - qt is also a salt & dissociate completely
Correct option-(B)