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Suppose we wish to conduct a survey to find p, the proportion of 1st year undergraduate students who hope to attend graduate

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Answer #1

We have given,
Preliminary estimate for proportion (Known) = 0.2
Margin of error =E=0.1/2=0.05....margin of error is half of the length of confidence interval
Level of significance =   1-0.94=0.06
Z critical value is (by using Z table) =1.881
Sample size formula is                   
n=\left [ \hat{p} (1-\hat{p})\right ]\left [ \frac{Z}{E} \right ]^2
=\left [ 0.20 (1-0.20)\right ]\left [ \frac{1.881}{0.05} \right ]^2
=226.44

c) 227
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