Implement MERGE-SORT() algorithm that reads from a file named
“inputHW02.txt” a list of double numbers (max = 3,000,000 numbers),
sorts those numbers and indicates time consumption. This
programming question will address the advantage of using iteration
loops over recursive calls as well as using INSERTION-SORT() as a
procedure in MERGESORT(). Your program must perform the following
actions:
1. Opens the given file name and reads all double numbers. For
simplicity, we assume this file only contains numbers and nothing
else.
2. Implements the function INSERTION-SORT() that only sort an array of maximum 25 numbers. The idea is that INSERTION-SORT() will be used as a sub-procedure to sort any sub-array when its size is small enough.
3. Four versions of MERGE-SORT() namely a. MERGE-SORT-A(): Using recursive calls and NO INSERTION-SORT() as a sub-procedure b. MERGE-SORT-B(): Using ITERATIVE loops (i.e, NO recursion) and NO INSERTION-SORT() as a subprocedure. c. MERGE-SORT-C(): Using recursive calls and INSERTION-SORT() as a sub-procedure. d. MERGE-SORT-D(): Using ITERATIVE loops (i.e, NO recursion) and INSERTION-SORT() as a subprocedure.
solution:
1.program to read the numbers from file:-
FILE *f=fopen("inputHW02.txt");
int intergersarray[10000]; //array to store values from text file
int i=0,num;
while(fscanf(f,%d,&num) && !feof(f)) //reads until it reaches the end of file
{
intergersarray[i]=num;
i++;
}
fclose(f);
2.implementation of insertion sort as a sub procedure:
INSERTION_SORT(int array[], int n)
{
int i,val,j;
for(i=1;i val=array[i]; j=i-1; while(j>=0&&array[j]>val){ array[j+1]=array[j]; j--; } array[j+1]=key; } } 3.MERGE-SORT-A: void mergesort(int array[],int l,int r){ int m=l+(r-1)/2 mergesort(array,l,m); mergesort(array,m+1,r); merge(array,l,m,r); } } void merge(int array[],int l,int m,int r){ int i,j,k; int p=m-l+1; int q=r-m; int L[p],R[q]; for(i=0;i
L[i]=array[l+i]; } for(j=0;j R[i]=array[m+1+j]; } i=0; j=0; k=l; while(i
if(L[i]<=R[i]){ arr[k]=L[i]; i++; } else{ array[k]=R[j]; j++; } k++; } while(i
arr[k]=L[i]; i++; k++; } while(j arr[k]=R[j]; j++; k++; } } MERGE_SORT_B:- void merge(int array[],int l,int m,int r){ int i,j,k; int p=m-l+1; int q=r-m; int L[p],R[q]; for(i=0;i
L[i]=array[l+i]; } for(j=0;j R[i]=array[m+1+j]; } i=0; j=0; k=l; while(i
if(L[i]<=R[i]){ arr[k]=L[i]; i++; } else{ array[k]=R[j]; j++; } k++; } while(i
arr[k]=L[i]; i++; k++; } while(j arr[k]=R[j]; j++; k++; } } MERGE_SORT_C: here we are performing insertion sort in the insertion sort if
the array size is less than 25. void mergesort(int array[],int l,int r){ if(r-l <= 25){ insertion_sort(array,l,r); else{ int m=l+(r-1)/2 mergesort(array,l,m); mergesort(array,m+1,r); merge(array,l,m,r); } } void insertion_sort(int array[],int l,int r){ int val; for(i=l;i val=array[i]; j=i-1; while(j>=l&&array[j]>val){ array[j+1]=array[j]; j--; } array[j+1]=key; } } void merge(int array[],int l,int m,int r){ int i,j,k; int p=m-l+1; int q=r-m; int L[p],R[q]; for(i=0;i
L[i]=array[l+i]; } for(j=0;j R[i]=array[m+1+j]; } i=0; j=0; k=l; while(i
if(L[i]<=R[i]){ arr[k]=L[i]; i++; } else{ array[k]=R[j]; j++; } k++; } while(i
arr[k]=L[i]; i++; k++; } while(j arr[k]=R[j]; j++; k++; } } MERGE_SORT_D: if(r-l<=25){ insertionsort(array,l,r); else{ void insertion_sort(int array[],int l,int r){ int val; for(i=l;i val=array[i]; j=i-1; while(j>=l&&array[j]>val){ array[j+1]=array[j]; j--; } array[j+1]=key; } } void merge(int array[],int l,int m,int r){ int i,j,k; int p=m-l+1; int q=r-m; int L[p],R[q]; for(i=0;i
L[i]=array[l+i]; } for(j=0;j R[i]=array[m+1+j]; } i=0; j=0; k=l; while(i
if(L[i]<=R[i]){ arr[k]=L[i]; i++; } else{ array[k]=R[j]; j++; } k++; } while(i
arr[k]=L[i]; i++; k++; } while(j arr[k]=R[j]; j++; k++; } }
if(l
void
mergeSort(
int
array[],
int
n)
{
int
current;
int
l;
for
(current=1;current<=n-1;current =
2*current)
{
for
(l=0;l
{
int
m=min(left+current-1,n-1);
int
r=min(l+ 2*current-1,n-1);
merge(arr,l,m,r);
}
}
}
void
mergeSort(
int
array[],
int
n)
{
int
current;
int
l;
for
(current=1;current<=n-1;current =
2*current)
{
for
(l=0;l
{
int
m=min(left+current-1,n-1);
int
r=min(l+ 2*current-1,n-1);
merge(arr,l,m,r);
}
}
}
}
Implement MERGE-SORT() algorithm that reads from a file named “inputHW02.txt” a list of double numbers (max...
Implement MERGE-SORT() algorithm that reads from a file named “inputHW02.txt” a list of double numbers (max = 3,000,000 numbers), sorts those numbers and indicates time consumption. This programming question will address the advantage of using iteration loops over recursive calls as well as using INSERTION-SORT() as a procedure in MERGESORT(). Your program must perform the following actions: 1. Opens the given file name and reads all double numbers. For simplicity, we assume this file only contains numbers and nothing else....
Implement MERGE-SORT() algorithm that reads from a file named “inputHW02.txt” a list of double numbers (max = 3,000,000 numbers), sorts those numbers and indicates time consumption. This programming question will address the advantage of using iteration loops over recursive calls as well as using INSERTION-SORT() as a procedure in MERGESORT(). Your program must perform the following actions: 1. Opens the given file name and reads all double numbers. For simplicity, we assume this file only contains numbers and nothing else....
Implement MERGE-SORT() algorithm that reads from a file named “inputHW02.txt” a list of double numbers (max = 3,000,000 numbers), sorts those numbers and indicates time consumption. This programming question will address the advantage of using iteration loops over recursive calls as well as using INSERTION-SORT() as a procedure in MERGESORT(). Your program must perform the following actions: 1. Opens the given file name and reads all double numbers. For simplicity, we assume this file only contains numbers and nothing else....
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