Question

A chandelier with mass m is suspended from a cable with mass M from the ceiling....

A chandelier with mass m is suspended from a cable with mass M from the ceiling. Take a Y-axis vertically up and apply Newton's 2nd law to find the magnitude of the tension at the top and at the bottom of the rope. Treat the weight w of the chandelier and the weight of the cable W as given. Draw a free body diagram for both the rope and the chandelier.

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
A chandelier with mass m is suspended from a cable with mass M from the ceiling....
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A 1400lb chandelier is to be suspended over a large ballroom, the chandelier will be hung...

    A 1400lb chandelier is to be suspended over a large ballroom, the chandelier will be hung on a cable whose ends will be attached to the ceiling, 18 ft apart. The chandelier will be free hanging so that the ends of the cable will make equal angles with the ceiling. If the top of the chandelier is to be 18 ft from the ceiling, what is the minimum tension the cable must be able to endure?

  • A chandelier with mass m is attached to the ceiling of a largeconcert hall by...

    A chandelier with mass m is attached to the ceiling of a large concert hall by two cables. Because the ceiling is covered with intricate architectural decorations (not indicated in the figure, which uses a humbler depiction), the workers who hung the chandelier couldn't attach the cables to the ceiling directly above the chandelier. Instead, they attached the cables to the ceiling near the walls. Cable 1 has tension T1 and makes an angle of θ1 with the ceiling. Cable...

  • Figure 1) A chandelier with mass m is attached to the ceiling of a large concert...

    Figure 1) A chandelier with mass m is attached to the ceiling of a large concert hall by two cables. Because the ceiling is covered with intricate architectural decorations (not indicated in the figure, which uses a humbler depiction), the workers who hung the chandelier couldn't attach the cables to the ceiling directly above the chandelier. Instead, they attached the cables to the ceiling near the walls. Cable 1 has tension T_1 and makes an angle of theta_1 with the...

  • 10. A piñata of mass 10.00 kg is suspended from the ceiling by means of three...

    10. A piñata of mass 10.00 kg is suspended from the ceiling by means of three ropes, as shown in the diagram. Find the tension in the left rope, right rope, and bottom rope if the angle a = 33.00° and B 18.00°. Assume that the acceleration due to gravity is 9 = 9.800 1 m s? 8 В 11. Tallula, who has a mass of 60.0 kg, is in a spaceship located 1055 km above the surface of the...

  • bailof mass M is suspended by a thin string (of negligible mass) from the ceiling of...

    bailof mass M is suspended by a thin string (of negligible mass) from the ceiling of an elevator. The vertical motion of the elevator as it travels up and down is descnibed in the statements below. Indicate for each of the situations described the relation between value of the tension in the cable, T, and the weight of the ball, Mg, or whether one Cannot teil. (Assume that there is no air, .e., neglect the buoyancy effect of the air)...

  • A mass m1=5.0 kg hangs suspended by a rope from an elevator ceiling. A second mass...

    A mass m1=5.0 kg hangs suspended by a rope from an elevator ceiling. A second mass m2=5.0 kg hangs suspended by a rope from the bottom of mass m1. Starting from rest, the elevator ascends, attaining its maximum speed of 1.8 m/s in 0.80 s. The elevator travels with this constant speed for 5.0 s, undergoes a uniform negative acceleration for 1.5 s, and then comes to rest. Draw a FBD for each mass Find the tension in each rope...

  • A 310-kg chandelier is suspended from vertical steel cable. The cable is 6.9 m long. Assume...

    A 310-kg chandelier is suspended from vertical steel cable. The cable is 6.9 m long. Assume a safety factor of 7.5. The elastic modulus for steel is 2.0×1011N/m2, and tensile strength for steel is 5.0×10^8N/m2. How much does the cable elongate? I got 4.56*10^-5 for the minimum cross sectional area required

  • An aluminum cable with cross-sectional area 1.50 times 10^-6 m^2 is suspended from the ceiling. A...

    An aluminum cable with cross-sectional area 1.50 times 10^-6 m^2 is suspended from the ceiling. A mass is suspended from the free end of the cable to keep the cable straight and at a certain length. If the temperature of the cable is reduced by 10 C degree, by how much should the suspended mass be increased so that the length of the cable remains the same? The coefficient of linear expansion for aluminum is alpha = 23 times 10^-6...

  • Two boxes, each of mass 2.0 kg. are connected by a rope. acceleration= 5 m/s^2 A.)...

    Two boxes, each of mass 2.0 kg. are connected by a rope. acceleration= 5 m/s^2 A.) draw a free body diagram for each box B.) considering the ropes are lightweight... B1.)what is the tension in the top rope? B2.) what is the tension of the rope connecting the two boxes? C.)considering the ropes are steel cables with a mass of 1.0 kg... C1.) what would be the force of the steel cable on the top box? C2.) what would be...

  • #8 Mechanical Equilibrium: suspended blocks A 10.4 kg mass is suspended from the ceiling with a...

    #8 Mechanical Equilibrium: suspended blocks A 10.4 kg mass is suspended from the ceiling with a cable of negligible mass. A 12.5 kg mass is attached (and suspended below) the 10.4 kg mass with a cable, also of negligible mass. What are the tensions, respectively, connecting the 10.4 kg mass to the ceiling (cable 1) and the cable connecting the 12.5 kg mass to the 10.4 kg mass (cable 2) O A. cable 1: 102 N; cable 2: 123 N...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT