(i)
Interpretation of intercept -
Annual income of man is 25 thousand dollars when the mean annual
income of his father was 0 dollars at age 40.
Interpretation of slope -
Annual income of man will increase by 0.5 thousand dollars when the
mean annual income of his father at age 40 will increase by one
thousand dollar.
(ii)
For annual income of father = $50,000
= 50
Thus, predicted annual income of man is 50 thousand dollars.
(iii)
For a $20,000 increase in the father, will increase by
20.
Effect on annual income of man = 20 * 0.5 = 10
Thus, annual income of man will increase by $10,000 with $20,000 increase in the annual income of father.
(iv)
Let the estimated regression equation be,
By converting the data to 2013 dollars by multiplying by 2.83, we get
Thus, for the new regression equation, slope will remain same as
The intercept will change as,
Suppose that a random sample of 200 40-year old men is selected from a population and...
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Suppose that a random sample of 184 twenty-year-old men is selected from a population and that their heights and weights are recorded. A regression of weight on height yields Weight (91.4572) 3.6248x Height, R2 = 0.745, SER = 9.3840 (1.9780) (0.2852) where Weight is measured in pounds and Height is measured in inches A man has a late growth spurt and grows 1.3800 inches over the course of a year. Construct a confideence interval of 95% for the person's weight...
Suppose a random sample of 200 20-year-old men is selected from a population and their heights and weights are recorded. A regression of weight on height yields \ Weight = −99.41 + 3.94(Height),R2 = 0.81,SER = 10.2 SE for beta_hat_0=(2.15), SE for beta_hat_1= (0.31) where Weight is measured in pounds and Height is measured in inches. Two of your classmates differ in height by 2 inches. Construct a 99% confidence interval for the differences in weights.
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