Question

Please I need ALL STEPS on how the change and the End was calculated. Do not just fill the table without showing calculations please. I also want to understand. Same goes for the conversion of benzene show all steps pls!

Consider the complete combustion of benzene in a reactor. C6H6 + 7.5 02 +6CO2 + 3 H2O Fill out the table below completely. Find the conversion based on benzene and the extend of reaction à. Start [mol] Change [mol] End [mol] Species CoH 02 40 10 CO2 HO Ar

Answer 1

sol . Giver, C GHG+ 7.5 or 600% + 3420 mole = PCCH = 5 mole : 5 mo By Exkent of reaction, + CHEE CH, sn Stichiomatic weficient - 5+UE 1 for reactant 5-1 & -3 {= 5-1 = 4 - 40 - 7.5x4 - 40 - 30 = lomake - 10 + 6 (4) = 34 mole = no one tvę = 2 +3 (4) = 14 mole how anim tvę = 30 + 0 = 30 mole out Conversion of benzene = "CCHE - CHE 501 0.8 - 80%

change (mol): for reactants, it is consumption . for products, it is generation. C6H6 = out in 2.1-5 - - 4 moles [ consumption out - in 10 - 40 = -3o moles [ consumption] out in 10 = 24 moles [generation] [generation] = 14-2= la moly Ar = out in = 30-30 = omoly component won't participate ů the [Ineet component] reaction. Note: Srect