A 1500 kg car traveling at a speed of 10 m/sskids to a halt on wet concrete where μk = 0.60.
How long are the skid marks?
Express your answer using two significant figures.
L=...
initial velocity vi = 10 m/s
final velocity vf = 0
initial kinetic energy ki = (1/2)*m*vi^2
final kinetic energy Kf = (1/2)*m*vf^2
frictional force fk = uk*m*g
work done by frictional force Wf = f*L*cos180 =
-uk*m*g*L
from work energy theorem
work = change in kinetic energy
-uk*m*g*L = (1/2)*m*(vf^2-vi^2)
-0.6*9.8*L = (1/2)*(0-10^2)
distance L = 8.5 m <<<<<------ANSWER
A 1500 kg car traveling at a speed of 10 m/sskids to a halt on wet...
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