Question

A graduated cylinder contains 16.5 mL of water. What is the new water level after 39.4 g of silver metal with a density of 10,5 g/mL is submerged in the water? Express your answer using three significant figures.

Answer 1

Volume of silver = mass (g) /density (mL) = (39.4/10.5) = 3.75 mL

Now total volume = (volume of water + volume of silver )

= (16.5 + 3.75) = 20.25 mL $\approx$ 20.2 mL (round off to 3 significant figure).

new water level is 20.2 mL.

part B

volume of mercury = mass(g) /density(g/mL) = (7.4 /13.6 )

= 0.54 mL. (Two significant figure).

hence, 0.54 mL mercury has spilled .