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(10 pts) A sag vertical curve is designed with the PVC at station 10900 and elevation...
7. A sag vertical curve connects a-4.75% grade and a +3.75% grade. The PVI is at...
7. A sag vertical curve connects a-4.75% grade and a +3.75% grade. The PVI is at station 45+90.00 at an elevation of 611.00 ft. The design speed is 50 mi/h. Determine the minimum length of the vertical curve using the AASHTO method ("K" factors). Round the minimum length up to the next 10 ft multiple for design of the vertical curve and associated calculations. Using this length, determine: The station and elevation of the PVC The station and elevation of...
a) a 200 m vertical crest curve is designed to connect a +4.5% tangent with a...
a) a 200 m vertical crest curve is designed to connect a +4.5% tangent with a -2% tangent. What should the design speed be to provide ample stopping sight distance? SSD t Pra) [10 marks) b) A 300 m sag parabolic vertical curve has a PVC at station 2+600.000 and elevation 320.000 m. the initial grade is -4.0% and the final grade is +1.0%. Determine the stationing and elevation of PVI, PVT and the lowest point on the curve. Also...
A 200m equal tangent sag vertical curve has the PVC at station 3 + 700.000 and...
A 200m equal tangent sag vertical curve has the PVC at station 3 + 700.000 and elevation 321m. The initial grade is -3.5% and the final grade is 0.5%. Determine the elevation and stationing of the PVI, PVT, and lowest point on the curve.
The data given for a vertical sag curve on a roadway plan and profile sheet are...
The data given for a vertical sag curve on a roadway plan and profile sheet are as follows: PVI station 32+11.61, PVI elevation 54.18 ft, back tangent gradient gi4.00 percent, forward tangent gradient g, 7.00 percent, and length of curve L- 600 ft. Determine the curve elevations at half-station intervals along the curve, and compute the sta elevation of the lowest point. tion and い600 ft PVT 35+11.61 Elev. 75.18 35 34 PVC 29 11.61 Elev 66.18 Low point 31...
13. A 400-ft long equal tangent sag vertical curve has its PVC at station 100+00 and o b elevation 500 ft, the init...
13. A 400-ft long equal tangent sag vertical curve has its PVC at station 100+00 and o b elevation 500 ft, the initial grade g,--4% and the final grade g2 elevation of the lowest point of the curve. +2.5%. Determine the
Question 3 (10 marks) A 1,500ft long sag vertical curve (equal tangent) has a PC at...
Question 3 (10 marks) A 1,500ft long sag vertical curve (equal tangent) has a PC at stenine 1,500f. The initial grade is -3% and the fina on 3+70 and elevation I grade is +6%. Determine the elevation and station 3+70 and a PVC at stationing of the low point, PVI, and PVT
A sag vertical curve has a 25% grade that intersects with a +3.1% grade at station...
A sag vertical curve has a 25% grade that intersects with a +3.1% grade at station 352+52.8 and an elevation of 422.8. To provide proper cover for a culvert, the elevation at 349+30.00 be 434.6 or higher. A) What minimum length of vertical curve is necessary to provide the necessary cover and meet the other design requirements for a design speed of 70 mph? B) if a 1025-foot curve is used, determine the station and the elevation of the low...
2. Given a sag vertical curve connecting a -1.5% grade with a +2.5% grade on a...
2. Given a sag vertical curve connecting a -1.5% grade with a +2.5% grade on a rural arterial highway, use the rate of vertical curvature and a design speed of 70 mi/h to compute the elevation of the curve at 100 ft stations if the grades intersect at station (475+00) at an elevation of 300.00 ft. Identify the station and elevation of the low point.
Question: An existing tunnel needs to be connected to a newly constructed bridge with sag and...
Question: An existing tunnel needs to be connected to a newly constructed bridge with sag and crest vertical curves. The sag curve begins at station 0+00 and elevation 100 ft. and the crest curve ends at station 12+00 and elevation 140 ft. Station 12 +00, PVT Bridge deck elevation 140 ft Tunnel floor elevation 100 ft WURUK Station 0 + 00, PVC, Develop a vertical alignment to connect the tunnel and bridge by determining the highest possible common design speed...
A sag vertical curve will connect two tangents, a -3% grade and a +5% grade, 800...
A sag vertical curve will connect two tangents, a -3% grade and a +5% grade, 800 ft apart. The ravine in which the sag curve will be situated needs to be built up. The elevation of the curve at its deepest point must be at elevation 168.00 ft or higher to clear a major pipe installation. If the PVC is at station 00 + 00.00 with an elevation of 176.20 ft, determine the location of the deepest point of the...
7. A sag vertical curve connects a-4.75% grade and a +3.75% grade. The PVI is at station 45+90.00 at an elevation of 611.00 ft. The design speed is 50 mi/h. Determine the minimum length of the vertical curve using the AASHTO method ("K" factors). Round the minimum length up to the next 10 ft multiple for design of the vertical curve and associated calculations. Using this length, determine: The station and elevation of the PVC The station and elevation of...
a) a 200 m vertical crest curve is designed to connect a +4.5% tangent with a -2% tangent. What should the design speed be to provide ample stopping sight distance? SSD t Pra) [10 marks) b) A 300 m sag parabolic vertical curve has a PVC at station 2+600.000 and elevation 320.000 m. the initial grade is -4.0% and the final grade is +1.0%. Determine the stationing and elevation of PVI, PVT and the lowest point on the curve. Also...
The data given for a vertical sag curve on a roadway plan and profile sheet are as follows: PVI station 32+11.61, PVI elevation 54.18 ft, back tangent gradient gi4.00 percent, forward tangent gradient g, 7.00 percent, and length of curve L- 600 ft. Determine the curve elevations at half-station intervals along the curve, and compute the sta elevation of the lowest point. tion and い600 ft PVT 35+11.61 Elev. 75.18 35 34 PVC 29 11.61 Elev 66.18 Low point 31...
13. A 400-ft long equal tangent sag vertical curve has its PVC at station 100+00 and o b elevation 500 ft, the initial grade g,--4% and the final grade g2 elevation of the lowest point of the curve. +2.5%. Determine the
Question 3 (10 marks) A 1,500ft long sag vertical curve (equal tangent) has a PC at stenine 1,500f. The initial grade is -3% and the fina on 3+70 and elevation I grade is +6%. Determine the elevation and station 3+70 and a PVC at stationing of the low point, PVI, and PVT
A sag vertical curve has a 25% grade that intersects with a +3.1% grade at station 352+52.8 and an elevation of 422.8. To provide proper cover for a culvert, the elevation at 349+30.00 be 434.6 or higher. A) What minimum length of vertical curve is necessary to provide the necessary cover and meet the other design requirements for a design speed of 70 mph? B) if a 1025-foot curve is used, determine the station and the elevation of the low...
2. Given a sag vertical curve connecting a -1.5% grade with a +2.5% grade on a rural arterial highway, use the rate of vertical curvature and a design speed of 70 mi/h to compute the elevation of the curve at 100 ft stations if the grades intersect at station (475+00) at an elevation of 300.00 ft. Identify the station and elevation of the low point.
Question: An existing tunnel needs to be connected to a newly constructed bridge with sag and crest vertical curves. The sag curve begins at station 0+00 and elevation 100 ft. and the crest curve ends at station 12+00 and elevation 140 ft. Station 12 +00, PVT Bridge deck elevation 140 ft Tunnel floor elevation 100 ft WURUK Station 0 + 00, PVC, Develop a vertical alignment to connect the tunnel and bridge by determining the highest possible common design speed...
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