Question

Determine the reactions at A and D. Determine the tension in the cable. D 4 ft 20 lb/ft 25 lb-ft 3ft E A 4 ft 10 ft 2 ft B

Answer 1

Fs0 beam ABC 6 ft 5 ft 5ft MA 2S b Tco Cose 3 sind 200 tb Ray 6-09 RA+ Tco Cose o RAx-3TCD RAy t Tep Sine -200 0 RAyt yTco +Ey=0 = 200 C+MA O MA-25 +16(Tep Sine) - 11 (200) = 0 MA t 64Tco 2225 (3

FBD of sechon BC Tco By Gy 200 1b G+EMB=O10 (Teosine)-5(200) - o Teo 125Jb Erom e's get we RAx=75 b (Oinechon opp. to what we assumed) 1 100 db Ray100 b MA625 Jb-ft 11 F8D ot joit D foy Ror Toc Rox=Tpe Cose oy loc Sine= 125 125/3 75b 100 2b

Reachons at A RAM7516 Ce) Kay- 100lb (1) Reachions at D Ron 75b () Roy l00lb(1) = 625 lb-G) MA Tension in the cable = 125 b