Question

Determine the tension developed in each cable. Due to symmetry, the tension in the four cables is the same.

The resultant of the four forces shown in (Figure 1) is FR={-350k} lb. Part A Determine the tension developed in each cable. Due to symmetry, the tension in the four cables is the same. Express your answer to three significant figures and include the appropriate units. View Available Hint(s) Figure << 1 of 1 > GÅR ? FA = Fp = Fc = Fp = Value Units Submit 6 ft < Return to Assignment Provide Feedback 2 ft X 2 ft B 3 ft

Answer 1

given E FR = (-350 k} lb solution OB = V 32+22 = JB fut tan 89 = love 88 = tan'( 13 ) on = 31° due to Symmetry OA= 08= 0 = 0% =0 = 31° t FA = F2 = Fe = F = F lacking Component of Tension. Here Horizontal component of forces will Cancel each other. so there is no resultant of force in Horizontal direction. Taking vertical component F COSOA + FB COS OB + F Cos de t Ep (osop - FR

A COSO X F = Fe F = FR coso = 4350k} .lb 4X10551 F = 4102.08 k} lb F = {102.08 k} lb down ward