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A heat engine using a diatomic gas follows the cycle shown in the figure. Its temperature at point 1 is 10.0 Part A °C. (Figu

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Solution Solution Temporchont a T = 10.0°C Placan) Determine w o and ot Now Diatomic gas (2 5/R and ep 2 7/2R Now using Idealat point 3 Voa uva V3 Pazpi T3 - Pa Va - PX X uy x 283 Р I To = 1132k] for process 12 workdone = POV=0.5X(40-10)+1( (1.5-0.5)

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