.data
A: .word 84 111 116 97 108 32 105 115 32
. text
main:li $v0, 1l
li $s0,0
la $s1, A
li $t3, 0
loop: slti $t0, $s0, 17
beq: $t0, $zero, end
sll $t1, $s0 2
add $t2 $s1 $t1
syscall
addi $s0, $s0, 1
j loop
end: li $v0, 1
add $a0, $zero, $t3
syscall
/// whats the output of above assembly program
Please find the output of the given code below::
There is issue in printing content of A for the given code.
If want to print content of A in character format than the correct code is as below>>>
.data
A: .word 84 111 116 97 108 32 105 115 32
.text
li $v0,11
li $s0,0
la $s1,A
li $t3,0
loop: slti $t0, $s0, 17
beq,$t0,$zero, end
sll $t1, $s0 2
add $a0 $s1 $t1
syscall
addi $s0, $s0, 1
j loop
end: li $v0, 1
add $a0, $zero, $t3
syscall
output:
.data A: .word 84 111 116 97 108 32 105 115 32 . text main:li $v0,...
what is the output of the following assembly code ? .data A: .word 84 111 116 97 108 32 105 115 32 . text main:li $v0, 1l li $s0,0 la $s1, A li $t3, 0 loop: slti $t0, $s0, 17 beq: $t0, $zero, end sll $t1, $s0 2 add $t2 $s1 $t1 syscall addi $s0, $s0, 1 j loop end: li $v0, 1 add $a0, $zero, $t3 syscall
im trying to complete mips program code about a calculator program that can calculate integer addition / subtraction written using the MIPS assembler. im having hard times to debug this. The input is given to the array of Formula char (base address $ s0) in the form of a formula. The null character (\ 0, ASCII code 0) is placed at the end. The calculation result is given to the register $ s1 and the overflow is ignored. For example,...
I have this MIPS program and I'm having trouble with it. This program is user inputs numbers until zero and sorts and print the numbers in order. Please soove this issue. You can use any sorting algorithm except bubble sort. Need it as soon as possible. Here is the code:.datanum: .word 0space: .byte ' ' .text main: # la $t0, val # loads val into a register # li $t1, 0 #keeps track of how many numbers entered la $a0,...
WRITE THE FOLLOWING CODE IN FLOATING POINT NUMBERS IN ASSEMBLY LANGUAGE USING MIPS IN MARS .data prompt: .asciiz "\nMaximum number is : " prompt1: .asciiz "\nMinimum number is : " prompt2: .asciiz "\nRange of the array is : " size: .word 10 #load array array: .word 23, -12, 45, -32, 52, -72, 8, 13,22,876 .text #load address of array and size la $s4,array #load address of A lw $t0,size #load i to t0 jal getArrayRange li $v0, 4 la...
.data prompt: .asciiz "Input an integer x:\n" result: .asciiz "Fact(x) = " .text main: # show prompt li $v0, 4 la $a0, prompt syscall # read x li $v0, 5 syscall # function call move $a0, $v0 jal factorial # jump factorial and save position to $ra move $t0, $v0 # $t0 = $v0 # show prompt li $v0, 4 la $a0, result syscall # print the result li $v0, 1 # system call #1 - print int move $a0,...
please trace this is sort program and base address s0, number of element s1 please also complete the program(..) explain the program too thanks sit $t4, $t1, $to beq $t4, $zero, Skip sll $s1, $s1, 2 add $s2, $s0, $s1 addi $t2, $so, 0 Skip: oopl: addi $t3, $t2, 0 oopJ: addi $t3, $t3, 4 beq $t3, $s2, NextI Iw $to, 0($t2) lw NextI: addi $t2, $t2, 4 End: 配列の昇順ソートベースアドレス$50, 空欄を埋めてプログラムを完成させよ。 要素数$51 sit $t4, $t1, $to beq $t4, $zero, Skip...
Please comment the MIPS code to help me understand. Here is what the code accomplishes. Here is the code, partially commented. .data Matrix: .word 41,45,5, 34,8, 15,16,23,44,48,12,32,18,47,22,8,22 .word 46,40,42,33,13,38,27,6, 29,25,18,40,47,22,26,14,3 .word 7, 48,35,9, 43,38,9, 49,28,25,42,5, 44,10,5, 38,14 .word 46,33,16,6, 13,20,31,1, 8, 17,1, 47,28,46,14,28,7 .word 32,2, 48,25,41,29,14,39,43,46,3, 39,32,49,41,28,46 .word 5, 43,2, 48,13,4, 33,41,32,19,9, 25,30,22,2, 9, 40 .word 14,47,22,18,47,3, 35,44,18,6, 33,22,11,6, 47,50,4 .word 28,34,20,30,18,27,38,5, 26,40,37,23,16,13,37,8,7 .word 48,38,39,12,10,39,23,20,21,20,33,16,24,21,25,3,46 .word 49,38,40,38,13,47,5, 13,4, 13,23,26,12,30,29,29, 3 .word 8, 20,10,13,31,7, 12,41,12,21,28,26,43,14,35,10,19 .word 49,33,25,26,24,29,46,22,7, 5, 15,41,10,31,19,41,27 .word 48,9,...
Assignment 4 File “quad_sol.s” contains a quadratic polynomial solver, which calculates the integer solution of a quadratic polynomial equation. 1. Rewrite the program using instructions reordering to reduce the number of cycles needed to execute the program. Indicate the number of cycle reduction. 2. Describe how forwarding would affect the execution of the program. CODE # quad_sol.s # This assembly program calculates the integer solutions of a quadratic polynomial. # Inputs : The coefficients a,b,c of the equation a*x^2 +...
Complete count_bits function. You are given an 32-bits integer stored in $t0. Count the number of 1's in the given number. For example: 1111 0000 should return 4 j main ############################################################### # Data Section .data # new_line: .asciiz "\n" space: .asciiz " " double_range_lbl: .asciiz "\nDouble range (Decimal Values) \nExpected output:\n1200 -690 104\nObtained output:\n" swap_bits_lbl: .asciiz "\nSwap bits (Hexadecimal Values)\nExpected output:\n75757575 FD5775DF 064B9A83\nObtained output:\n" count_bits_lbl: .asciiz "\nCount bits \nExpected output:\n20 24 13\nObtained output:\n" swap_bits_test_data: .word 0xBABABABA, 0xFEABBAEF, 0x09876543 swap_bits_expected_data: .word...
.text main: ori $s7,$0,4097 # put a memory location in $s7 sll $s7,$s7,16 # ori $s0,$0,0x2 # put 2 into $s0 and $s0,$s0,$zero # clear $s0 ori $s0,$zero,0x2 # put 2 back into $s0 nor $s0,$s0, $zero # complement $s0 ori $s0,$zero,0x2 # put 2 back into $s0 ori $s1,$0,0x3 # put 3 into $s1 add $s2,$s0,$s1 # add beq $s2,$zero, exit sw $s2, 4($s7) # store the result...