Question

A 105 A current circulates around a 1.70-mm-diameter superconducting ring.

Part A What is the ring's magnetic dipole moment? Express your answer with the appropriate units. 2.38×10−4 A⋅m2 SubmitMy AnswersGive Up Correct Part B What is the on-axis magnetic field strength 5.40 cmfrom the ring? Express your answer with the appropriate units. 2.98•10−6T SubmitMy AnswersGive Up Incorrect; Try Again; 4 attempts remaining

Answer 1

given currrent is 105A

diammeter of the ring is 1.7mm

now we have to find the

What is the ring's magnetic dipole moment?

What is the on-axis magnetic field strength 5.40 cmfrom the ring?

1) The magnetic moment ? = I*A = 105A*?*r^2 =105*?*(0.85x10^-3m)^2 = 2.38x10^-4A-m^2


2) Bx = ?o*I*r^2/(2*(r^2 + z^2)^3/2 = 4?x10^-7*105*(0.85x10^-3)^2/(2*((0.85x10... + 0.054^2)^3/2 =

5.62x10^-6T