Question 2 (5 points) A child on a sled (total mass 75 kg) coasts over a...

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Question 2 (5 points) A child on a sled (total mass 75 kg) coasts over a small hill in the snow at a speed of 3.5 m/s. The to

Answer 1

Answer #1

Since the body is moving in a circukar path.

Therefore,

The force of friction = Coefficient of kinetic friction X centripetal force

Now

Given

Coefficient of kinetic friction=.12

Radius=4.1m

Speed=3.5m/s

Therefore

Friction= (μmv^2)/R

= (.12x 75x3.5x3.5)/4.1

= 26.89N

≈27N

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Answer 2

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