You invest $280 in a mutual fund today that pays 9.10 percent interest annually. How long will it take to double your money? (If you solve this problem with algebra round intermediate calculations to 6 decimal places, in all cases round your final answer to 0 decimal places.)
future amount = amount invested*(1+r)^n
here,
future amount = 280*2 =>560.
amount invested = 280
r = 9.10%=>0.091.
n = to be found out.
560 = 280 *(1.091)^n
=>2 = 1.09^n
apply logarithms
=>log 2 = log (1.09)^n
=>log 2 = n log (1.09)
=>log 2 / log 1.09 = n
=>8.04323173
=>8 years.
It will take 8 years to double the money.
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