Question

MESSAGE HY INSTRUCTOR FULL SCREEN PRINTER VERSION BACK Chapter 05, Problem 38 GO A satellite has a mass of 5926 kg and is in a circular orbit 4.43 x 10 m above the surface of a planet. The period of the orbitis 1.hours. The radius of the planet is 4.73 x 10 m. What would be the true weight of the satelliteit were at rest on the planet's surface? w the tolerance is +/-296 Click if you would like to Show Work for this question: Open Show Work LINK TO TEKTUNK TO TEXT

please make answer and units clear! thanks

Answer 1

Here we apply keplKepl third law of planetary motion and Newton's law of gravitation.

- Ane Mass of satellite, M=59 26kg - radius of orbit, r= (4.43 x 108m + 4.73x100m) Mass of planet, Mp=? Time period of orbit, T= 1.6 horse - Kepler's third law a 472 G Mp -) GMO = 41483 477(4.43 x 105 +4.73 X1063 3 3 (1:6X 3600 sec)? GM = 5.24315 x103 Nm2 We know, . gravity cat surface of planet j = Goh Rp = 4.73 xlo^m g= 5.24 315 x10' Nm2/tr (4:73 x106m)? .R24 of Planet = 1 g = 7.3 624 m/s2 True Weight of satellite cat surface W = mg = 592679) (7.3624 m/s2) = 43,629.6 Newton