10 points 6. A proton is released from rest at the surface of a positively charged...

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Answer 1

Answer #1

Solution (Q) dv=- proton 05 0 05 (b) Consder a= acceleration of Proton Mp proton Mp

L9 0105 2 2 proton = 516,629 χ lo Ly 3Proton_ 32.144 X lo Proton in« ΤΟΥ)

Answer 2

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