Question

A 100 kg box is being pulled by a chain along a horizontal surface. The chain is at a 25 engle. The coefficient of friction between the box and surface is 0.46. The box starts from sest and travels 16 meters in 9 seconds. What is the acceleration, tension force and normal force for the box? Turn in all work for this question. Follow the procedure on page 115 for full credit. a) Acceleration b) Normal Force c) Tension Force

Answer 1

a)

acceleration,

d = 0.5 at^2

16 = 0.5* a * 9^2

a = 0.395 m/s^2

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b)

forces along horizontal

T cos x - u N = ma

Normal force

N = mg - T sin x... (i)

putting in above

T cos x - u ( mg - T sin x) = ma

T cos 25 - 0.46* ( 100* 9.8 - T sin 25) = 100* 0.395

T = 445.439 N

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c)

putting in (i)

N = 791.74 N

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