how much heat does it take to completely vaporize a 75.0g ice cube?
given:
ice = 0°C
T boiling point = 100°C
C water = 1cal/g°C
Lf = 80.0 cal/g
Lv = 540.0 cal/g
Solution
Using the relation heat energy,
Q = mL + mcwT + mL
= 75[80cal/g + [1cal/goC*100oC] + 540cal/g]
= 54000Cal.
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