Replace the 25k load at with a 20k load. Using the Method of Joints, solve for the forces in members BC, CD, DE, CE, and CF. Place your answers in the order shown Indude in your answer if the member is in compression (C) or tension (). Do not use negative signs in your results. Use Tor C to show the direction of the force. The superscript is a notation for kilopounds (1000 pounds). 20 12' 125*
Current assets: inventory 15K, cash 25K, debts receivables 10K non current assets: land 500K, plant and machinery 25K, investments 75K liabilities; credits/payables 150k, non current liabilities (loan) 100k. What is the owners equity?
Both half reactions and balanced equation Cr(CN)6 4- + Ce 4+ > Cr3+ + Ce 3+ + NO3 - + CO2
Balance the reaction below in basic solution. Ce^(4+)aq + I^(-)aq = Ce^(3+)aq + IO3^(-)aq
-6 at 30 ft = 180 ft- 25 k 25k 25L I 20 ft 15 ft 5 ft 45k (g) members CD, DI & DJ (method of sections)
[10pt] 4. Which of the following differential equations has solution (t) = ce-cost + ce-sint? a) 2" - 2x + 2x = 0 b)x"+ 2x' + 2x = 0 c) <"+ 23' - 2x = 0 d) ?" - 2x' - 2x = 0 e) None of these
Example2 25k A solid sphere (mass M, radius R) is released from rest at the top of an inclined plane (angle ?). There is sufficient friction between the incline and the sphere to allow it to roll without slipping. (a) Draw and FBD for the sphere. (b) Find the linear acceleration of the sphere (c) Find the magnitude of the frictional force acting on the sphere. (d) Find the minimum required coefficient of friction to keep the sphere from slipping....
Ce Ce Ce Ce You are titrating 100.0 mL of 0.0400 M Fe2 in 1 M HCIO4 with 0.100 M Ce to give Fe and Ce E E-0.767-0.05916log 0.24I using Pt and calomel electrodes to find the endpoint. (a) Write the balanced titration reaction. Fe aq)Ce (aq)Fe (b) Complete the two half reactions for (d) Calculate the values of E for the cell when the following volumes of the Ce titrant have been added: (Activity coefficients may be ignored as...
1. A proposed mechanism for the oxidation of thallium(I) by the cerium(IV) ion is: Ce+4(aq) + Mn+2(aq) Ce+3(aq) + Mn+3(aq) Ce+4(aq) + Mn+3 (aq) → Ce+3(aq) + Mn+4(aq) Mn4+(aq) + Tl+(aq) → Mn+2(aq) + Tl+3(aq) (a) Write the balanced chemical equation for the overall reaction described by this mechanism. (b) Write the chemical formula(s) for all intermediates involved in this mechanism. (c) Write the chemical formula(s) for all catalyst(s) involved in this mechanism (d) Write the overall rate law predicted by...
8f-4f-4 PROBLEM 4 Determine the support reactions and the force in member CE for the truss shown in the figure below: 300 lb D E 8 ft B 1000 lb 8f- -8 ft-