Question

1) A particle of charge 2 C is momentarily located at the position (8,5, 2) [all distances in meters). The particle's velocity is 200i + 100j + 350k (in m/s] What is the magnetic field vector due to the particle at the position (8, 10, 2)? [Use the first answer box for Bo, the second for By, and the third for B2.] Answer 1 of 3: Answer 2 of 3: Answer 3 of 3:1 Submit All Answers 2) At that same instant, a second particle of charge -5 C is momentarily located at the origin, moving along the positive z-axis with a speed of 1300 m/s. What is the total magnetic field at the target position from the previous problem? [Use the first answer box for B1, the second for By, and the third for B2.] Answer 1 of 3: Answer 2 of 3: Answer 3 of 3: Submit All Answers

Answer 1

0 2 2 20 , &- ditsit 2 k v = 200 i tlooj + 350k r = 82 +10 +2k Magnetic field due to a moving charge B = M. qW x) 43 - F - 5 3x8 - (2001 +100; + 350k) x 5; = 1000(Êx} + 5001jxV) +(35045) (k x1) - 1000 r tot 1750-2 3x7 2 1000 R - 1750i B 42 x10 x 2 (1000-17502) ad 42 3 R16x10" [R-17537 B = -28 x 107 T By - 0 B = 16810T 2-5 , 1300 i da 8 it ou + 27 - Southoorn a 168 = 12.96 Jxo - 13000 - 2600 48x15 x 5 x (130001 - 2600]) _ (13000) - 65000 k to 42 (12.963 2176.8

B = (5.97% - 29.86 k) x 10 To tal magnetic field at point or- (8, 10,3). Be - Bit B - 28 x10-7+ 5.97x16" -1386X10E Bx = – 28x10-7 T By = 5.97x10 T Bz s - 13. 86 x 10 T
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