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Consider a source particle of charge qS=3 C located at (−7,−3) [distances in meters]. Find the...
1) Consider a source particle of charge qS=9 C located at (−9,5) [distances in meters]. Find the electric field vector at the target location (−15,15) [Enter the x-component in the first box, and the y-component in the second box]. 2) What is the magnitude of the electric field at the target location given above? 3) What is the direction of the electric field at the target location given above? Give your answer as an angle with respect to the positive...
1) A particle of charge -8 C is momentarily located at the position (2,2,1) [all distances in meters]. The particle's velocity is 500î + 100j + 150k [in m/s] What is the magnetic field vector due to the particle at the position (6,6, 3)? [Use the first answer box for Bę, the second for By, and the third for B2.] Answer 1 of 3: Answer 2 of 3: Answer 3 of 3: Submit All Answers 2) At that same instant,...
1.a) A particle of charge 5 μ C is located at the origin. A second particle of charge 4 μ C is located at the coordinates (2.57,3.06) in cm. What is the magnitude of the electric force between the particles? 1.b) What are the x and y components of the electric force acting on the particle at the point (2.57,3.06) ? [Enter the x component in the first box and the y component in the second box]
3.2 Electric Field of a Charged Particle The four properties of the electric field of a charged particle are captured by the vector field where the particle has charges and the source-to-target radial vector field and its associated unit vector field are defined as Psr (x,y) = (x - 1s)i + (- ) Pris(z,y) STIFT IFs (2.y) and k = 8.99 x 10°N C/ mºis Coulomb's constant. Question 3.3) Consider a 2 C source particle, located at the position (1,3)...
1) A particle of charge 2 C is momentarily located at the position (8,5, 2) [all distances in meters). The particle's velocity is 200i + 100j + 350k (in m/s] What is the magnetic field vector due to the particle at the position (8, 10, 2)? [Use the first answer box for Bo, the second for By, and the third for B2.] Answer 1 of 3: Answer 2 of 3: Answer 3 of 3:1 Submit All Answers 2) At that...
ou arrange two identical charges along the x-axis at positions (-2.0,0) and (2.0,0), with distances measured in centimeters. You've set things up so that the origin of your coordinates lies at the midpoint between the charges. You measure the electric force acting on the charge on the right and find it has a magnitude of 83082.0 N. You want to deduce the electric field vector that is acting on the right-hand charge. [Note that there are three answer boxes: enter...
4) A particle carrying 2 C of charge is located at the origin and moving with a velocity is = 5 km/s) 1. Calculate the magnetic field vector at the location Py = (3 cm)i + (2 cm) j - (7 cm). Calcualte the magnetic force vector on a 5 C particle at the given target location moving with velocity Oy = (6 km/s)i + (4 km/s) - (14 km/s) k.
Particle 1 is located at the Origin and carries 4.05 uC of charge. Particle 2 is located at x = 55.6 meters down the positive x axis and carries 1.28 uC of charge. Find the Electric Field between them at x = 10.25 meters along the positive x axis.
Particle 1 is located at the Origin and carries -3.29 uC of charge. Particle 2 is located at x = 49.7 meters down the positive x axis and carries -4.19 uC of charge. Find the Electric Field between them at x = 28.81 meters along the positive x axis.
Two charged particles are located in the X-Y Plane. Particle 1 carries 0.510 uC of charge and is located at x = 4.19 m and y = 1.48 m. Particle 2 carries 0.430 uC of charge and is located at x = -3.04 m and y = -4.69 m. Find the X component of the Electric Field at a Point located at x = 3.03 m and y = -0.32 m, in Newtons per Coulomb.