a] Let final temperature be T, Here heat lost by copper = heat gained by water
m1C1deltaT1 = m2C2deltaT2
0.2*387*[100-T] = 0.1*4186*[T-20]
T = 32.5 degree C
b] m1C1deltaT1 = m2C2deltaT2
0.100*C*[100-25] = 0.150*4186*[25-20]
T = 418.6 degree C
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