A) If 350 mL of 0.90 M HNO3 is diluted to
450 mL, what is the molarity of the resulting solution?
B) How many milliliters of water must be added to 152 mL of 1.50 M HCl to give 1.00 M HCl? (Assume the volumes are additive.)
How many milliliters of 10.5 M HCl(aq) are needed to prepare 740.0 mL of 1.00 M HCl(aq)? A 61.0 mL aliquot of a 1.20 M solution is diluted to a total volume of 238 mL. A 119 mL portion of that solution is diluted by adding 113 mL of water. What is the final concentration? Assume the volumes are additive. concentration:
of 10 > A 37.0 mL aliquot of a 0.400 M stock solution must be diluted to 0.100 M. Assuming the volumes are additive, how much water should be added? volume of water: volume of water:
76.0 mL of a 1.50 M solution is diluted to a total volume of 248 mL. A 124-mL portion of that solution is diluted by adding 151 mL of water. What is the final concentration? Assume the volumes are additive. Number
2. Calculate the molarity (M) of 30.0 g of NaOH in 350 mL of NaOH solution. Show all the step by step work: 3. Calculate the amount of solute, in moles, grams or milliliters, needed to prepare the following solutions. Show all the step by step solution: a. 1.00 L of a 3.00 M NaCl solution (moles of solute) b. 2.00 L of a 1.50 M NaOH solution (grams of solute) c. Milliliters of 1.50 M NaCl solution to obtain...
A 75.0 mL aliquot of a 1.50 M solution is diluted to a total volume of 208 mL. A 104 mL portion of that solution is diluted by adding 185 mL of water. What is the final concentration? Assume the volumes are additive. concentration: M
A 70.0 mL aliquot of a 1.50 M solution is diluted to a total volume of 248 mL. A 124 mL portion of that solution is diluted by adding 117 mL of water. What is the final concentration? Assume the volumes are additive.
A 67.0 mL aliquot of a 0.400 M stock solution must be diluted to 0.100 M. Assuming the volumes are additive, how much water should be added?
As a technician in a large pharmaceutical research firm, you need to produce 450. mL of a potassium dihydrogen phosphate buffer solution of pH = 6.93. The pKa of H2PO4− is 7.21. You have the following supplies: 2.00 L of 1.00 M KH2PO4 stock solution, 1.50 L of 1.00 M K2HPO4 stock solution, and a carboy of pure distilled H2O. How much 1.00 M KH2PO4 will you need to make this solution? (Assume additive volumes.) A beaker with 2.00×102 mLmL...
58.0 mL of a 1.70 M solution is diluted to a total volume of 238 mL. A 119-mL portion of that solution is diluted by adding 133 mL of water. What is the final concentration? Assume the volumes are additive.
64.0 mL of a 1.70 M solution is diluted to a total volume of 248 mL. A 124-mL portion of that solution is diluted by adding 195 mL of water. What is the final concentration? Assume the volumes are additive.