Solution:
First calculate moles from 75.0mL and 1.50 M:
75.0 mL x 1.50 M =112.5 mmol
This mmol diluted to a total volume of 208 mL
112.5 mmol / 208 mL = 0.5409 M
After that we take 104 mL above solution-
0.5409 M x 104 mL = 56.23 mmol
After that in this solution added 185 mL water
Total volume = 185 + 104 = 289 mL
56.23 mmol/289 mL = 0.1946 M
Hence the final concentration of the solution is =0.1946 M
A 75.0 mL aliquot of a 1.50 M solution is diluted to a total volume of...
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