Question

A 73.0 ml. aliquot of a 1.30 M solution is diluted to a total volume of 258 ml. A 129 ml. portion of that solution is diluted by kling 135 ml, of water. What is the final concentration? Assume the volumes are additive concentration:

Answer 1

Į By adding solvent (or) dilution mols ob solute won't change. no en - b) before dilution at after dilation. we know, n = n - n = mu - where , n moles m-) molasity 4) volume. from ③ and mou = mauat Griven, mb = 1.30m 1. mazo ub-73.oml va=258ml from - mouro (1.30m (73.0 m) [258m) 0.368 m Scanned with CamScanner

Now, 12a mi ob 0. 368m so is diluted by adding 135 m2 solvent Chao? olution again, mo = 0.368m i Ma=?. vb = 12ami in 129m2 + 135mL رل initial volume ho added 1. = 264mL. 3mar Co.368m) Cizated [26460 a = 0.180m :. Ans),- final concention on = 10.180 m Scanned with CamScanner