Question

24 of 26 (16 complete) N Score: 61.54%, 16 of 2. Score: 0 of 1 pt 9.9.38 Question Help Two catalysts in a batch chemical process are being compared for their effect on the output of the process reaction. A sample of 12 batches was prepared using catalyst 1 and gave an average yield of 85 with a sample standard deviation of 5. A sample of 14 batches was prepared using catalyst 2 and gave an average yield of 75 and a sample standard deviation of 4. Find a 90% confidence interval for the difference between the population means, assuming that the populations are approximately normally distributed with equal variances. Click here to view page 1 of the table of critical values of the t-distribution. Click here to view page 2 of the table of critical values of the t-distribution Let Hy be the population mean for catalyst 1 and let uz be the population mean for catalyst 2. The confidence interval is <H4-12 (Round to two decimal places as needed.)

Answer 1

hn -l 4,X2구s, S2-4 cni-Dstcn-Dasz Spe Itn2-2 C12-13(5)2 +C14-D42 1241나-2 4.4260 Sp Cf- nitn2-2 = 12 + I4-2 2 g0% CT 5 (-X2 to/2,0-1 Sp 2 85-75)1 to 1/2,24 X 4&860 1.7649 101 3.01귀) (10-3.0171, 10+3.0171) 6.9829 13.0141) 1 6.9829 < 의,- el2 < 13. 이기