Question

Problem 11.25 If an object on a horizontal frictionless surface is attached to a spring, displaced, and then released, it oscillates. Suppose it is displaced 0.128 m from its equilibrium position and released with zero initial speed. After 0.830 s , its displacement is found to be 0.128 m on the opposite side and it has passed the equilibrium position once during this interval.

Part A Find the amplitude of the motion. A = m SubmitMy AnswersGive Up Part B Find the period of the motion. T = s SubmitMy AnswersGive Up Part C Find the frequency of the motion. f = Hz SubmitMy AnswersGive Up

Answer 1

amplitude of the motion = maximum displacement

amplitude of the motion = 0.128 m

period of motion = one cycle of motion

half ctcle of motion is made in 0.830 sec

full cycle will be made in 2 * 0.830

time period = 1.66 sec

frequency = 1 / time period

frequency = 1 / 1.66

frequency = 0.6024 Hz