Question

WHETHER RECORDING DATA OR SHOWING CALCULATIONS, REMEMBER TO INCLUDE MEASUREMENT UNITS WITH EACH NUMERICAL VALUE. Volume of copper chloride solution in your sample final buret reading (read to 0.01-mL place) 30.5 ml 5.25 ml initial buret reading volume of copper chloride solution delivered Mass of copper chloride per mL (from stock solution label) 25.00 mL 0672 g/m 1.68 g compound Mass of copper chloride in your sample (show calculation) HO.3668 8 Mass of clean, dry, empty evaporating dish Mass of evaporating dish + copper: after first heating 0 after second heating 42. 9790 g 413080 & 41.336 . 0 after third heating (if necessary) 0

Answer 1

V copper chloride solution = 30.5 mL -5.25 mL = 25.5 mL D = 0.0672 g/ mL Mass of copper chloride = 0.0672 g/mL x 25.5 mL = 1.7136 g Mass of Cu recovered: After third heating : 42.9720 g -41.3668 g = 0.9693 g Mass empty dish of clean, dry, evaporating Mass of evaporating dish + Cu Mass of chloride : Mass of copper chloride = Mass of copper + mass of chloride mass of chloride = Mass of copper chloride - Mass of copper mass of chloride = 1.7136 g - 0.9693 g mass of chloride = 0.7443 g Moles of Cu: 1 mol Cu moles of Cu = 0.9693 g of Cu - 63.546 g Cu moles of Cu = 0.0153 mol Moles of CI: 1 mol cl moles of CI = 0.7443 g of CI 35.5 g CI moles of Cl = 0.021 mol Moles of Cl/ moles of Cu : moles of CI = 0.021 mol/0.0153 mol = 1.3 21 Cu = 1 CI = 1 Empirical formula: Cuci